From the mathematic function D(1?D)2 of (25), it can be observed if D value is at 1/3, the CC 5013 mathematic function D(1?D)2 will have the maximum value, which also means the maximum D value created by (25) is 1/3. Hence in designing inductance, when D as 1/3 is substituted into (25), and let the inductance value derived from calculation be multiplied by surplus value 1.25, it can be assured that the inductance current can really work in the continuous current mode.The load impedances of so-called light load and heavy load in this paper, are respectively, 2,020�� and 450��. So at switching frequency 15kHz, heavy load duty cycle about 0.85 when it is substituted into (25), the result is that in order to let the current continue under light load, the least inductance should be 6.
23mH, while under heavy load it should be 179��H. In this paper 260��H is the option to make it possible to be in continuous current conduction mode under heavy load.The change of output capacitor current is shown in the iCo of Figure 11. From Figure 11 we know the amount of capacitor electric charge change as|��Q|=VODTRO=CO��VO.(26)Then its voltage ripple ratio may be expressed as follows:��VOVO=DTROCO.(27)Figure 11The switch signal, inductance, and capacity waveforms under each operation mode.So the result isCO=DROf(��VO/VO).(28)Therefore in the converter, we can decide the size of the capacitor according to the amount of voltage ripple ratio. From (28) it is observed that the output capacity and duty cycle are in linear relation. It means the designed output capacity must be greater than the required capacity with the maximum duty cycle.
In this paper voltage ripple ratio is set at 5%. When it is substituted into (28), the output capacity is 2.5��F. So 150��F is selected to make the voltage ripple ratio lower than 5%.By means of the above-described operation mode of the converter, the switch control signal in the circuit, inductance and capacity current waveform can be exhibited in Figure 11, and its input voltage ripple and current ripple can be shown Ln��L1,L2,(29)��VCo=IODT.(30)From?in��Ii=(VO/2?ViLn?ViLn)(1?D)T=VO?4Vi2Ln(1?D)T; (29) it is known that the voltage-doubler boost converter has the advantage of lower input current but the amount of its output voltage ripple is the same as the traditional Cilengitide high voltage converter. Hence in this paper we set forth an ameliorated interleaved voltage-doubler boost converter. By means of the original voltage-doubler boost converter parallelly connected, making output voltage interleaved, so as to reduce output voltage ripple, the flaw of greater output voltage is further ameliorated.4.
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